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ACT Probability Practice Questions
Probability questions show up frequently in the Math section of the ACT. Below are practice questions taken from our bank to help you prepare.
More questions
A commuter has a 60% chance of missing the first train and a 40% chance of missing the second train, given that they missed the first train. What is the probability that the commuter misses both trains?
A commuter has a 60% chance of missing the first train and a 40% chance of missing the second train, given that they missed the first train. What is the probability that the commuter misses both trains?
A city's transit system has found that 40% of buses experience delays during morning rush hour on any given weekday. If a commuter takes the bus on both Tuesday and Wednesday mornings, what is the probability that the bus is delayed on at least one of these two days?
A commuter has a 60% chance of missing the first train and a 40% chance of missing the second train, given that they missed the first train. What is the probability that the commuter misses both trains?
Hard questions
A researcher studies 100 soybean plots: 30 high-yield (40 bushels), 50 medium-yield (30 bushels), and 20 low-yield (15 bushels). Two sampling methods estimate the population mean: Method A takes 10 random plots, while Method B takes 5 high-yield, 3 medium-yield, and 2 low-yield plots. What is the ratio of Method A's expected squared error to Method B's when estimating the mean yield?
A researcher studies 100 soybean plots: 30 high-yield (40 bushels), 50 medium-yield (30 bushels), and 20 low-yield (15 bushels). Two sampling methods estimate the population mean: Method A takes 10 random plots, while Method B takes 5 high-yield, 3 medium-yield, and 2 low-yield plots. What is the ratio of Method A's expected squared error to Method B's when estimating the mean yield?
A researcher studies 100 soybean plots: 30 high-yield (40 bushels), 50 medium-yield (30 bushels), and 20 low-yield (15 bushels). Two sampling methods estimate the population mean: Method A takes 10 random plots, while Method B takes 5 high-yield, 3 medium-yield, and 2 low-yield plots. What is the ratio of Method A's expected squared error to Method B's when estimating the mean yield?
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